IBPS PO is starting in 5 months (Oct, tentatively). You would know that “Permutations and Combinations” is a critical topic in PO exams. Once you understand concepts well, you can easily solve problems from Combinations. Below is a common type of problem witnessed by candidates in previous year PO exams.
A box contains 4 apples, 7 oranges, and 8 bananas. If four fruits are picked at random, how many number of ways at least 2 apples will be selected?
First, let us write down the possibilities for at least 2 apples in a draw of 4 fruits:
Possibilities for at least 2 apples =
(All 4 apples) OR
(3 apples AND (1 orange OR 1 banana )) OR
(2 apples AND 2 oranges) OR
(2 apples AND 2 bananas) OR
(2 apples AND 1 orange AND 1 banana) …equation 1
To solve this problem, we are going to apply a familiar formula:
Number of ways of selecting R items from N items is NCR
and NCR = N!/(N-R)!R!
Also, to solve equation 1 (and other similar equations in future) remember this: Replace “AND” with “x” (multiplication) and “OR” with “+”.
Let us now simplify equation 1 using the above logic and formula.
No of ways = 4C4 +
4C3 * (7C1 + 8C1) +
4C2 * 7C2 +
4C2 * 8C2 +
4C2 * 7C1 *8C1
Now if we calculate the combination values using the formula NCR = NCR = N!/(N-R)!R!, we will get:
No of ways = 1 + 4 * (7 + 8) + 6 * 21 +6 * 28 +6 * 7 * 8
= 1 + 60 + 126 + 168 + 336
Therefore, your answer is 691
We hope that the above problem and solution will help you. All the very best!
IBPS Exams 2017 are beginning in 4-5 months from now (PO in Oct and RRB in Sep, tentatively). Prepare fast and well to make use of the big opportunity. All the best.
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