Probability Solved Questions For IBPS, SBI and Other Bank Exams - Page 2

You will find 14 problems in 4 pages..

Probability Problems Solved Questions (Page 2 of 4)

Question 1

Two dice are thrown simultaneously. What is the probability of getting the sum of the face number is odd?
a) 1/3 b) 2/3 c) 1/2 d) 3/4

Answer:c) 1/2

Solution:

In a simultaneous throw of two dice, we have n(s) = 6 x 6 = 36
Let E = event of getting two numbers whose sum is odd.
Then E = { (1,2), (1,4), (1,6), (2,1), (2,3), (2,5), (3,2), (3,4), (3,6), (4,1), (4,3), (4,5), (5,2), (5,4), (5,6), (6,1), (6,3), (6,5)}
therefore, n(E) = 18
And P(E) = p( getting two numbers whose sum is odd)
P(E) = n(E)/n(s) = 18/36 = 1/2

Hence the answer is 1/2


Question 2

Two dice are thrown simultaneously. What is the probability of getting the sum of the face number is at least 10?
a) 1/6 b) 1/3 c) 2/3 d) 5/6

Answer:a) 1/6

Solution:

In a simultaneous throw of two dice, we have n(s) = 6 x 6 = 36
Let E = event of getting two number whose sum is at least 10.
Then E = { (4,6), (5,5), (5,6), (6,4), (6,5), (6,6) }
therefore, n(E) = 6
And P(E) = p( getting two numbers whose sum is at least 10)
P(E) = n(E)/n(s) = 6/36 = 1/6

Hence the answer is 1/6


Question 3
Two dice are thrown simultaneously. What is the probability of getting the sum of the face number is at most 5?
a) 2/18 b) 5/18 c) 4/9 d) 2/9

Answer:b) 5/18

Solution:

In a simultaneous throw of two dice, we have n(s) = 6 x 6 = 36
Let E = event of getting two numberswhose sum is at most 5.
Then E = { (1,1), (1,2), (1,3), (1,4), (2,1), (2,2), (2,3), (3,1), (3,2), (4,1)}
therefore, n(E) = 10
And P(E) = p( getting two numbers whose sum is at most 5)
P(E) = n(E)/n(s) = 10/36 = 5/18

Hence the answer is 5/18


Question 4
Two dice are thrown simultaneously. What is the probability of getting the face numbers are same?
a) 1/6 b) 2/3 c) 4/9 d) 5/6

Answer:a)1/6

Solution:

In a simultaneous throw of two dice, we have n(s) = 6x6 = 36
Let E = event of getting two numbers are same.
Then E = { (1,1), (2,2), (3,3), (4,4), (5,5), (6,6)}
therefore, n(E) = 6
And P(E) = p( getting two numbers are same)
P(E) = n(E)/n(s) = 6/36 = 1/6

Hence the answer is 1/6


Probability Problems Solved Questions (Page 2 of 4)

Prepare Fast And Score Well In SBI & IBPS, PO & Clerk Exams

Related pages


ashashare comantonyms for stridenteasy venn diagramstock exchange examslongest platform of indiawww paisaboltahai rbi org inmadhya pradesh international airportpermutation and combination problems with solutionsbanking exam bookscomputer for ibps pocube root questions and answersbanking abbreviationssyllogism tutorialibps clerks examsbi technoparkhard aptitude questions with solutionssbi bank papercomputer aptitude questionsnabard establishedpermutations and combinations solved problemsvysya bank careersgrama bankcistern pipecareer in sbi banksums on hcf and lcmquantitative aptitude tutorialsindia international airports listbanking notes for bank examsbank under ibpsibps clerk salarygk current affairvysya bank careerssbi clerk exam 2014syllogism online testprofit loss formulassbi bank clerical examrtgs upper limitinequalities exam questionsprofit & loss formulaslogical reasoning aptitude questionspermutations and combinations problemscareers sbimaths profit and losssurds and indices questions and answers pdfformulas related to profit and lossvysya bank careersrbi was establishedverbal reasoning for bank examsibps clerk salarybank of baroda rajasthansitting arrangement reasoningairport names in indiasyllogism questions and answerssbi bank exam preparationmensuration sumsbank ibps potmb bank exambanking abbreviationsibps sbireasoning questions for bank examaptitude test on probabilityibps officialsyllogism questions and answers with explanationsbi exam 2014antonyms of divulgesolved examples on permutation and combinationcomputer aptitude questionschief ministers of india listpremutation and combinationfirst bank to introduce atm